# Ohm’s Law

## The relation between Voltage and Current

What we’ve been doing till now is looking into the different terms related to a circuit separately. It’s time that we find out whether there exists a relation between them or not. After all, they seem to be related, don’t they?

Imagine that the pump from our water pump system normally pushes 1000 molecules of water through the pipe every second. Lately, it has been working out in the gym. Because of this new found energy, instead of 1000 molecules, it can now push 1500 water molecules every second! **This means that as the pressure applied by the pump increases the rate of flow of water molecules also increases.** What if, one day it was feeling lazy, or ill? It won’t be able to generate pressure required to push even 1000 molecules.

This hypothetical situation shows that the rate of flow of the water molecules depends on the pressure that the pump applies. As the pressure increases, the rate of flow increases; as it decreases, so does the rate of flow. But there is a condition: the length and thickness of the pipe should remain the *same*.

Now, we very well know how much an electronic circuit resembles a water pump system. So does the relationship between the different parameters. Hence, similar to the flow of water, in an electronic circuit, the current *increases* with an *increase* in voltage, and *decreases* as the voltage *decreases*. This is the Ohm’s Law: one of the most basic, yet important laws in physics. It states that:

## Ohm’s Law

*The current flowing through a conductor is directly proportional to the voltage across it provided its resistance remains constant.*

Mathematically, the Ohm’s law can be written as:

** V = R × I**

where,

**V** represents the voltage across the terminals of the resistor in volts (V)

**R** represents resistance in ohms (Ω)

**I** represent current in amperes (A)

## How to use Ohm’s Law

If we know any two of the three quantities, we can easily find out the third.

Let’s take the example that we took white talking about the unit of resistance. Suppose you have a simple circuit with a battery of *9V* and a resistor. The current in the circuit is *3A*. According to Ohm’s law,

**R = V/I**

Therefore,

**R= 9/3=3Ω**

In order to practically observe the working of the law, we will perform an activity. But before that, there one more thing that we must look into. We’ll quickly go through it and then continue with our activity!